document.write( "Question 1168368: A car leaving a stop sign accelerates constantly from a speed of 0 feet per
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document.write( "second to reach a speed of 44 feet per second. The distance of the car from the stop sign,d, in feet, at time t, in seconds, can be found using the equation d=1.1t^2 .
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document.write( "What is the average speed of the car, in feet per second, between
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document.write( "t = 2 and t = 5?
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document.write( "A. 5.5
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document.write( "B. 6.6
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document.write( "C. 7.7
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document.write( "D. 8.5
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Algebra.Com's Answer #792952 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! A car leaving a stop sign accelerates constantly from a speed of 0 feet per \n" ); document.write( "second to reach a speed of 44 feet per second. The distance of the car from the stop sign,d, in feet, at time t, in seconds, can be found using the equation d=1.1t^2 . \n" ); document.write( "What is the average speed of the car, in feet per second, between \n" ); document.write( "t = 2 and t = 5? \n" ); document.write( "-------------- \n" ); document.write( "d(t) = 1.1t^2 \n" ); document.write( "d(2) = 4.4 feet \n" ); document.write( "d(5) = 27.5 feet \n" ); document.write( "---- \n" ); document.write( "d(5) - d(2) = 23.1 feet \n" ); document.write( "23.1/3 = 7.7 ft/sec \n" ); document.write( " |