document.write( "Question 1168350: The probability of a Hat being red is 1/4.
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document.write( " The probability of a Hat being green is 1/4
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document.write( " The probability of a Hat being white is 1/2
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document.write( " The probability of a Hat being red or white is __ \n" );
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Algebra.Com's Answer #792937 by Edwin McCravy(20055)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "P(R or W) = P(R) + P(W) - P(R and W)\r\n" ); document.write( "\r\n" ); document.write( "The hat can't be both red and white because \r\n" ); document.write( "\r\n" ); document.write( "P(R) + P(G) + P(W) = 1/4 + 1/4 + 1/2 = 1, so P(R and W) = 0\r\n" ); document.write( "\r\n" ); document.write( "P(R or W) = P(R) + P(W) - P(R and W) = 1/4 + 1/2 - 0 = 1/4 + 2/4 = 3/4 \r\n" ); document.write( "\r\n" ); document.write( "Or we could have just done it this way: \r\n" ); document.write( "\r\n" ); document.write( "P(R or W) = P(not G) = 1 - 1/4 = 4/4 - 1/4 = 3/4\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |