Algebra.Com's Answer #792916 by ikleyn(52788)  You can put this solution on YOUR website! . \n" );
document.write( "The sum of 128 consecutive odd, positive integers is the greatest power of two less than 200,000. \n" );
document.write( "The sum of the least and the greatest of these integers is 2^N. What is the value of N? \n" );
document.write( "~~~~~~~~~~~~~~~\r \n" );
document.write( " \n" );
document.write( " \n" );
document.write( "\n" );
document.write( "\r\n" );
document.write( " = 17.61 (approximately, with two decimals).\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Therefore, the greatest power of 2 less than 200,000 is = 131072.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "So, the sum of 128 consecutive odd positive integers is 131072.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "These consecutive integer numbers form an arithmetic progression;\r\n" );
document.write( "\r\n" );
document.write( "therefore, their sum is the product of the number of terms (128) by half the sum of the least and the greatest of these two numbers.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "In other words, = .\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "It is equivalent to\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( " = , or\r\n" );
document.write( "\r\n" );
document.write( " = , or\r\n" );
document.write( "\r\n" );
document.write( " = .\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "It implies 17 = N + 6, or N = 17 - 6 = 11.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "ANSWER. N = 11.\r\n" );
document.write( " \r \n" );
document.write( "\n" );
document.write( "Solved.\r \n" );
document.write( " \n" );
document.write( " \n" );
document.write( "\n" );
document.write( " \n" );
document.write( " |