document.write( "Question 1168306: A carpenter had two apprentices for a job. The carpenter worked 6 hours longer than the apprentice. The second apprentice worked twice as long as the first. If the carpenter and his carpenter and his apprentices worked a total of 22 hour, how long did the carpenter work? \r
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document.write( "1st apprentice = x, 2nd apprentice = 2x, carpenter = 6x
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document.write( "x + 2x + 6x = 22
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Algebra.Com's Answer #792913 by josgarithmetic(39620)![]() ![]() ![]() You can put this solution on YOUR website! --------------------------------------- \n" ); document.write( "he carpenter worked 6 hours longer than the FIRST apprentice. The second apprentice worked twice as long as the first. \n" ); document.write( "-------------------------------------\r \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "Carpenter 6+f\r\n" ); document.write( "First apprent. f\r\n" ); document.write( "Second apprent. 2f\r\n" ); document.write( "TOTAL 22\r\n" ); document.write( " \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "! \n" ); document.write( " |