document.write( "Question 1168261: find two integers with a product of -40 and a sum of -3 \n" ); document.write( "

Algebra.Com's Answer #792868 by VFBundy(438) $\"\"$ $\"About$

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xy = -40
\n" ); document.write( "Let y = -40/x
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\n" ); document.write( "x + y = -3
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\n" ); document.write( "x - 40/x = -3
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\n" ); document.write( "x²/x - 40/x = -3
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\n" ); document.write( "(x² - 40)/x = -3
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\n" ); document.write( "x² - 40 = -3x
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\n" ); document.write( "x² + 3x - 40 = 0
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\n" ); document.write( "(x - 5)(x + 8) = 0
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\n" ); document.write( "x = 5 and x = -8
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\n" ); document.write( "If x = 5, y = -8.
\n" ); document.write( "If x = -8, y = 5.
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\n" ); document.write( "So, the two integers are 5 and -8. \n" ); document.write( "

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