document.write( "Question 1168121: The time it takes Jessica to bicycle to school is normally distributed, with a mean time of 15 minutes and a variance of 4 minutes. Jessica has to be at school at 8:00am. What time should she leave her house so she will be late only 4% of the time? \n" ); document.write( "
Algebra.Com's Answer #792800 by Theo(13342)![]() ![]() You can put this solution on YOUR website! the mean is 15 minutes. \n" ); document.write( "the variance is 4 minutes. \n" ); document.write( "standard deviation = sqrt(variance) = sqrt(4) = 2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "use an online calculator such as the one found at http://davidmlane.com/hyperstat/z_table.html\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "select value from an area. \n" ); document.write( "set area to .04 \n" ); document.write( "set mean to 15 \n" ); document.write( "set standard deviation to 2. \n" ); document.write( "select above.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "calculator says 18.501 minutes to get to school is exceeded only 4% of the time.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "confirm by doing the following:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "select area from a value \n" ); document.write( "set mean to 15 \n" ); document.write( "set standard deviation to 2 \n" ); document.write( "select above \n" ); document.write( "enter 18.501 into above \n" ); document.write( "hit return\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "calculator says 18.501 minutes to get to school is exceeded only 4% of the time.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "what this says is that if she leaves 18.501 minutes before 8:00 am, she will be on time 96% of the time and she will be late 4% of the time.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that's because the trip takes more than 18.501 minutes only 4% of the time.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "18.501 minutes is equal to 18 minutes and 30.06 seconds.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "to find out when she needs to leave home, subtract 0:18:30.06 from 8:00:00.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you will get 7:41:29.94.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that's when she has to leave home so that she late only 4% of the time.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "8:00:00 minus 7:41:29.94 = 7:59:60 minus 7:41:29.94 resulting in 00:18:30.06.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "00:18:30.06 is equal to 18.501 minutes.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you divide the 30.06 seconds by 60 to get .501 minutes.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you add it to 18 minutes to get 18.501 minutes.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "here's the displays of the results using the online calculator.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "first display is value from an area.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "second display is area from a value.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "obviously, getting her to leave her house at 7:41:29.94 am is highly unrealistic.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "she would probably want to leave her house at 7:40 am.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that would give her 20 minutes to get to school and she would only be late less than 1% of the time (the calculator says .62% of the time).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "here's a display of 20 minutes to get to school.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you solution, without rounding, is that she needs to leave her home by 7:41:29.94 am.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |