document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1168139>Question 1168139</A>: <I><SPAN STYLE=\"word-break: break-all;\">   On six days in a week two cities had the same daily average temperature. But because of sudden drop in the temperature on the seventh day in one of the cities. the average weekly temperature of the two cities differ by 0.5 degree.  The difference between the six days average daily temperature of two cities and the seventh day temperature of the other city is: </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #792787 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=792787\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> mean=total/n<BR>\n" );
document.write( "so n*mean=total<BR>\n" );
document.write( "the total was 6* mean for each after 6 days.<BR>\n" );
document.write( "on the 7th day 7*meanA for warmer and 7*meanB for cooler=total<BR>\n" );
document.write( "we know mean A-0.5=mean B<BR>\n" );
document.write( "Change over 7 days means a 3.5 degree drop for mean B\r<BR>\n" );
document.write( "\n" );
document.write( "example 60/60/60/60/60/60/60=total 420 and mean of 60 after 6 days and after 7 days<BR>\n" );
document.write( "60/60/60/60/60/60/x. Here the average has to be 59.5 so the total will be 416.5.  That means the temperature on the last day has to be 56.5\r<BR>\n" );
document.write( "\n" );
document.write( "3.5 degrees<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );