document.write( "Question 1168145: A survey of a group's web habits for the past month obtained the following information.\r
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document.write( "36% visited Facebook.
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document.write( "34% visited LinkedIn.
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document.write( "31% visited Google.
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document.write( "19% visited Facebook and LinkedIn.
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document.write( "16% visited Facebook and Google.
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document.write( "16% visited LinkedIn and Google.
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document.write( "9% visited all three sites.\r
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document.write( "Find the percentage that visited none of these three sites last month. \n" );
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Algebra.Com's Answer #792782 by ikleyn(52781)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( " p = 100% - (36% + 34% +31%) + (19% + 16% + 16%) - 9% = 41%. ANSWER\r\n" ); document.write( "\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |