document.write( "Question 1168159: At RSM summer camp 100 students had enough food for a 30-days stay. After 2 days 40 new students joined the camp. After that 2 weeks passed and half of the students left the camp. How many additional days of food need to be ordered? \n" ); document.write( "
Algebra.Com's Answer #792765 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "There is some good basic arithmetic in this problem; but the question that is asked makes no sense....

\n" ); document.write( "The camp starts with enough food for 100 students for 30 days.

\n" ); document.write( "After the first 2 days, there is enough food for 100 students for 30-2 = 28 days.

\n" ); document.write( "Then 40 new students joined the camp. That means the number of students increased by a factor of 140/100 = 1.4. And that means the number of days the food will last decreases by a factor of 1.4. So the food will last the 140 students for 28/1.4 = 20 days.

\n" ); document.write( "Then, after the next two weeks (14 days), there will be enough food for the 140 students for 20-14 = 6 days.

\n" ); document.write( "At that point, half the students leave the camp. That means the number of days the food still on hand will last doubles; so there is now enough food on hand for the 70 remaining students for 6*2 = 12 days.

\n" ); document.write( "There is nowhere in this scenario where any more food needs to be ordered....

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