document.write( "Question 1168124: Scores on a standardized exam are known to follow a normal distribution with a standard deviationĪ of = 8. A researcher randomly selects 84 students and finds their mean exam score to be (X with the bar over it) = 78. How confident are you that the mean score for all students taking the exam is in the interval (76.702, 79.298)?
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Algebra.Com's Answer #792744 by Theo(13342)![]() ![]() You can put this solution on YOUR website! standard deviation of the population is 8. \n" ); document.write( "sample size is 84. \n" ); document.write( "sample mean is 78.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the standard error is equal to the population standard deviation divided by the sample size.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this is equal to 8 / sqrt(84) = .8728715609\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "use a normal distribution calculator to find the proportion of scores between 76.702 and 79.298 when the mean score is 78 and the standard error of a sample size of 84 is equal to .8728715609.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your result will be that the proportion is equal to .8629972264.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that's your confidence level.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you are confident that 86.3% of samples of size 84 will have a mean that falls between 76.702 and 79.298.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "100 - 86.3 = 13.7% of the samples will have a mean that falls outside these limits.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "half of the 13.7% will fall below 76.782 and the other half of the 13.7% will fall above 79.298.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "here's a display of the calculator results, rounded to whatever rounding rules the calculator has.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the online calculator says that the probability that the scores will be within those limits is .863.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "round .8629972264. to 3 decimal digits and it becomes .863.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that online calculator can be found at http://davidmlane.com/hyperstat/z_table.html\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that calculator rounds the results to .863.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the TI-84 Plus calculator that i use (a physical calculator, not an online calculator, gave me the results rounded to a lot more decimal digits.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "it does not, however, provided a nice online display such as the display from the online calculator.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |