document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1168127>Question 1168127</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A phone company offers two monthly plans. Plan A costs $11 plus an additional $0.12 for each minute of calls. Plan B costs $17 plus an additional $0.10 for each minute of calls.<BR>\n" );
document.write( "For what amount of calling do the two plans cost the same?<BR>\n" );
document.write( "What is the cost when the two plans cost the same?<BR>\n" );
document.write( "$ </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #792743 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=792743\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 11+0.12m=17+0.10m is the equation needed, a linear equation with a constant monthly cost and a variable of minutes used<BR>\n" );
document.write( "0.02m=6<BR>\n" );
document.write( "m=300  so 300 minutes.\r<BR>\n" );
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document.write( "then A is $11+$36 or $47 and B is $17 + $30 or $47. </SPAN>\n" );
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