document.write( "Question 108562: Use the LCD to determine which fraction is greater\r
\n" ); document.write( "\n" ); document.write( "27. 5/2,7/3\r
\n" ); document.write( "\n" ); document.write( "Any help with this equation would be greatly appreciated:)
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Algebra.Com's Answer #79274 by HyperBrain(694)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "\"5%2F2=%284%2B1%29%2F%282%29=%284%2F2%29%2B%281%2F2%29=2%2B1%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"7%2F3=%286%2B1%29%2F%283%29=%286%2F3%29%2B%281%2F3%29=2%2B1%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "Let's compare \"2%2B1%2F2\" and \"2%2B1%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "\"2%2B1%2F2\" ? \"2%2B1%2F3\"
\n" ); document.write( "\"2-2%2B1%2F2\" ? \"2-2%2B1%2F3\"
\n" ); document.write( "\"0%2B1%2F2\" ? \"0%2B1%2F3\"
\n" ); document.write( "\"1%2F2\" ? \"1%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "NOte: if two fractions are given to be \"1%2Fp\" and \"1%2Fq\", and p < q, then \"1%2Fp\" is greater than \"1%2Fq\"\r
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\n" ); document.write( "\n" ); document.write( "Thus, \"1%2F2\" is greater than \"1%2F3\" and therefore, \"5%2F2\" is greater than \"7%2F3\"\r
\n" ); document.write( "\n" ); document.write( "SINCE 2 and 3 are prime to each other then their least common multiple (LCM) is \"2%2A3=6\"\r
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\n" ); document.write( "\n" ); document.write( "Power up,
\n" ); document.write( "HyperBrain!
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