document.write( "Question 1168080: The weight of a sophisticated running shoe is normally distributed with a mean of 12 ounces
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document.write( "and a standard deviation of 0.5 ounces.
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document.write( "a. What is the probability that a shoe weighs more than 13 ounces?
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document.write( "b. What must the standard deviation of weight be in order for the company to state that 99.9%
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document.write( "of its shoes are less than 13 ounces? \n" );
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Algebra.Com's Answer #792697 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! z=(x-mean)/sd \n" ); document.write( "=(13-12)/0.5=2 sd \n" ); document.write( "the probability is z>2 or 0.0228 \n" ); document.write( "- \n" ); document.write( "99.9% is a z-value of 3.09 \n" ); document.write( "so 3.09=(1)/sd \n" ); document.write( "so sd has to be 1/3.09 or 0.324 oz. \n" ); document.write( " \n" ); document.write( " |