document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1168092>Question 1168092</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (x^(2)-11x)/(x-5) +(30)/(x-5)<BR>\n" );
document.write( "Add or subtract as indicated. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #792694 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=792694\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is( x^2-11x+30)/(x-5), since I can add the numerators with same denominators<BR>\n" );
document.write( "=(x-6)(x-5)/(x-5)<BR>\n" );
document.write( "=x-6, where x cannot equal 5. If one cancels the denominator, it still exerts an effect on the domain. </SPAN>\n" );
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