document.write( "Question 1168066: A particular fruit's weights are normally distributed, with a mean of 756 grams and a standard deviation of 14 grams.\r
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document.write( "The heaviest 20% of fruits weigh more than how many grams?\r
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document.write( "Give your answer to the nearest gram. \n" );
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Algebra.Com's Answer #792676 by Theo(13342)![]() ![]() You can put this solution on YOUR website! the mean is 756 grams. \n" ); document.write( "the standard deviation is 14 grams\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "look into the z-score table.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you want to find the z-score with an area of .2 to the right of it. \n" ); document.write( "the z-score table only shows the area to the left of the z-score. \n" ); document.write( "subtract .2 from 1 to get .8. \n" ); document.write( "you want to find the z-core with an area of .8 to the left of it. \n" ); document.write( "that will be the same z-score with an area of .2 to the right of it.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the z-score table that i use can be found at https://www.math.arizona.edu/~rsims/ma464/standardnormaltable.pdf\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "looking into the table, i found:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "an area of .79955 is associated with a z-score of .84 \n" ); document.write( "an area of .80234 is associated with a z-score of .85\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the difference between those areas is .00279 and the difference between those z-scores is .01\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "take the highest area and subtract .2 from it to get a difference of .00234. \n" ); document.write( "divide that difference from the overall difference of .00279 to get a ratio of .00234 / .00279 = .8387096774. \n" ); document.write( "multiply the difference between the two z-scores of .01 to get .01 * .8387096774 = .0083870968. \n" ); document.write( "subtract .008370968 from the z-score of .85 to get a z-score of .85 - .008370968 = .841612903323.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that's a reasonably close approximation of what the real z-score should be. \n" ); document.write( "you can also use a z-score calculator that will also get you presumably more accurate answer with a lot less headaches.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the z-score calculator on the TI-84 Plus that i have gave me a z-score of .84162122335. \n" ); document.write( "the z-scores are the same out to 4 decimal digits which is usually good enough.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "anyway, now that you have the z-score, you can solve for the raw score.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the z-score formula is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "z = (x - m) / s\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "z is the z-score \n" ); document.write( "x is the raw score \n" ); document.write( "m is the mean \n" ); document.write( "s is the standard deviation or the standard error\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "in this case, s is the standard deviation.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "replace m and s and z with their respective values to solve for x.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you get .841612903323 = (x - 756) / 14. \n" ); document.write( "solve for x to get x = .841612903323 * 14 + 756 = 767.7825806.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "80% of the raw scores will be less than that and 20% of the raw scores will be higher than that.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that can be seen through the use of the following calculator that can be found at https://www.omnicalculator.com/statistics/normal-distribution\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "here's a display of the results of using that calculator.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "my inputs were mean of 756 standard deviation of 14 and p(x > X) of .2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the calculator filled in the rest.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "it told me that the value of X was 767.783.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that's very close to the raw score i calculated manually of 767.783 rounded to 3 decimal places.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "unless you have to use the tables and do the manual interpolation, the recommendation is to use the calculator.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "it's much easier.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "anyway, round the raw score to the nearest gram to get 768 grams as your answer.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "fyi, i used the z-score that i manually calculated through interpolation. \n" ); document.write( "in most cases, i would just use the z-score i got through the use of a calculator. \n" ); document.write( "i only did it manually to show you how the interpolation works. \n" ); document.write( "if you use the tables, you could also just use the z-score associated with the area closest to the one that you want and that will be good enough. \n" ); document.write( "your instructor should be your guide as to how close an answer you need to get.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |