document.write( "Question 1168029: You need to estimate the proportion of United States citizens that support an increase in off-shore drilling. You take a random sample of 1851 citizens and find that 651 support an increase in off-shore drilling. Construct a 95% confidence interval for the population proportion.\r
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Algebra.Com's Answer #792633 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! p hat=651/1851=0.352 \n" ); document.write( "95% half-interval is z(0.975)*sqrt (phat*(1-phat)/n) \n" ); document.write( "=1.96* sqrt (0.352*0.648/1851) \n" ); document.write( "=+/-0.0218 or 0.22 \n" ); document.write( "(0.330, 0.374) \n" ); document.write( "Use 0.373, with rounding, rather than 0.370. \n" ); document.write( " |