document.write( "Question 1167951: The height y (in feet) of a ball thrown by a child is y= −1/14x² + 4x + 5 where x is the horizontal distance in feet from the point at which the ball is thrown.\r
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document.write( "(a) How high is the ball when it leaves the child's hand? \r
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document.write( " ? feet\r
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document.write( "(b) What is the maximum height of the ball? \r
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document.write( " ? feet\r
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document.write( "(c) How far from the child does the ball strike the ground? Round your answers to the nearest 0.01. \r
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document.write( " ? feet\r
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document.write( "I need help on this one!!! \n" );
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Algebra.Com's Answer #792630 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! It is 5 feet high, the constant in the equation. \n" ); document.write( "- \n" ); document.write( "vertex is at x=-b/2a or -4/-1/7 or 28 \n" ); document.write( "when x=28 then y=-56+112+5=61 ft. \n" ); document.write( "- \n" ); document.write( "it strikes the ground when y=0 \n" ); document.write( "rewrite quadratic as -x^2+56x+70=0 or x^2-56x-70=0 \n" ); document.write( "x=(1/2)(56+/- sqrt (3136+280)) sqrt term=58.45 \n" ); document.write( "x=57.22 ft.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |