document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1168001>Question 1168001</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Bob had enough money to buy 25 chocolate cookies. Each chocolate cookie cost as much as 2 butter cookies. He borrowed another 6 dollars to buy 20 chocolate and 20 butter cookies. \r<BR>\n" );
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document.write( "How much money did he have at first?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #792594 by </B><A HREF=/tutors/aboutme.mpl?userid=VFBundy><B>VFBundy(438)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=VFBundy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=VFBundy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=792594\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Cost of one chocolate cookie = x<BR>\n" );
document.write( "Cost of one butter cookie = 0.5x<BR>\n" );
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document.write( "25x + 6 = 20x + 20(0.5x)<BR>\n" );
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document.write( "25x + 6 = 20x + 10x<BR>\n" );
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document.write( "25x + 6 = 30x<BR>\n" );
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document.write( "5x = 6<BR>\n" );
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document.write( "x = $1.20<BR>\n" );
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document.write( "Since Bob originally had enough money to buy 25 chocolate cookies...and we know one chocolate cookie costs x dollars ($1.20)...that means 25 chocolate cookies cost $30.  So, Bob originally had $30. </SPAN>\n" );
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