document.write( "Question 1167984: 1. The square of a positive integer is 98 less than twice the square of the next consecutive integer. Find the integers. Show your solution.\r
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Algebra.Com's Answer #792590 by VFBundy(438)\"\" \"About 
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1. The square of a positive integer is 98 less than twice the square of the next consecutive integer. Find the integers.
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\n" ); document.write( "First integer = x
\n" ); document.write( "Second integer = x + 1
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\n" ); document.write( "x² = 2(x + 1)² - 98
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\n" ); document.write( "x² = 2(x² + 2x + 1) - 98
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\n" ); document.write( "x² = 2x² + 4x + 2 - 98
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\n" ); document.write( "x² = 2x² + 4x - 96
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\n" ); document.write( "x² + 4x - 96 = 0
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\n" ); document.write( "(x - 8)(x + 12) = 0
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\n" ); document.write( "x = 8 and x = -12
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\n" ); document.write( "Since the problem stated the integers were positive, we can eliminate the x = -12 result. We are left with x = 8. So...
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\n" ); document.write( "First integer = x = 8
\n" ); document.write( "Second integer = x + 1 = 9
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\n" ); document.write( "2. Find two integers differ by 4, while their squares differ by 56.
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\n" ); document.write( "First integer = x
\n" ); document.write( "Second integer = x + 4
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\n" ); document.write( "(x + 4)² - x² = 56
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\n" ); document.write( "x² + 8x + 16 - x² = 56
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\n" ); document.write( "8x + 16 = 56
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\n" ); document.write( "8x = 40
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\n" ); document.write( "x = 5
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\n" ); document.write( "First integer = x = 5
\n" ); document.write( "Second integer = x + 4 = 9
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