document.write( "Question 1167892: Hi
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document.write( "Elaine had some sweets. When she ate 2/7 of them and gave 36 to her brother she had 2/7 left. How many did she have at first.\r
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document.write( "Thanks \n" );
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Algebra.Com's Answer #792532 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "She ate 2/7 of the sweets and still had 2/7 of them left after she gave some to her brother. \n" ); document.write( "That means the 36 sweets she gave her brother were 3/7 of the number she started with. (2/7 plus 2/7 plus 3/7 = 7/7 = all of them) \n" ); document.write( "(3/7)x = 36 \n" ); document.write( "x = 36(7/3) = 12*7 = 84 \n" ); document.write( " \n" ); document.write( " |