document.write( "Question 1167914: Hi \r
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document.write( "Bill and Ben had some sweets. After giving away 5/7 of his sweets, Bill had 2/3 as many sweets as Ben. After Ben gave 120 sweets away he now had 1/4 as much as Bill.\r
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document.write( "How many sweets did each have at the start?\r
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document.write( "Thanks \n" );
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Algebra.Com's Answer #792514 by VFBundy(438) You can put this solution on YOUR website! Bill's sweets at start = x \n" ); document.write( "Ben's sweets at start = y \n" ); document.write( " \n" ); document.write( "2/7(x) = 2/3(y) \n" ); document.write( "y - 120 = 1/4(2/7(x)) \n" ); document.write( " \n" ); document.write( "Simplify equations: \n" ); document.write( " \n" ); document.write( "2/7(x) = 2/3(y) \n" ); document.write( "y - 120 = 1/14(x) \n" ); document.write( " \n" ); document.write( "2/7(x) - 2/3(y) = 0 \n" ); document.write( "-1/14(x) + y = 120 \n" ); document.write( " \n" ); document.write( "Multiply second equation by 2/3: \n" ); document.write( " \n" ); document.write( "2/7(x) - 2/3(y) = 0 \n" ); document.write( "-1/21(x) + 2/3(y) = 80 \n" ); document.write( " \n" ); document.write( "Add both equations together: \n" ); document.write( " \n" ); document.write( "5/21(x) = 80 \n" ); document.write( " \n" ); document.write( "Solve for x: \n" ); document.write( " \n" ); document.write( "x = 80(21/5) \n" ); document.write( " \n" ); document.write( "x = 336 \n" ); document.write( " \n" ); document.write( "Now that we know x = 336, we can plug this into any previous equation to find out what y equals. \n" ); document.write( " \n" ); document.write( "2/7(x) = 2/3(y) \n" ); document.write( " \n" ); document.write( "2/7(336) = 2/3(y) \n" ); document.write( " \n" ); document.write( "96 = 2/3(y) \n" ); document.write( " \n" ); document.write( "y = 96(3/2) \n" ); document.write( " \n" ); document.write( "y = 144 \n" ); document.write( " \n" ); document.write( "Bill's sweets at start = x = 336 \n" ); document.write( "Ben's sweets at start = y = 144 |