document.write( "Question 1167780: In a recent survey, it was found out that a certain college has 86 faculty members broken down as follows:\r
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document.write( " 48 female intructors
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document.write( " 46 married instructors
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document.write( " 34 instructors with more than 15 years service
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document.write( " 19 married female
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document.write( " 18 married with more than 15 years service
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document.write( " 17 female with more than 15 years service
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document.write( " 8 married female with more than 15 years service\r
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document.write( "Questions:
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document.write( "1. How many are married female with less than 15 years service?
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document.write( "2. How many are married male with more than 15 years service?
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document.write( "3. How many are single female with more than 15 years service?
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document.write( "4. How many are married female with more than 15 years service
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document.write( "5. How many are male single with less than 15 years service?\r
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document.write( "
Algebra.Com's Answer #792469 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You can't answer number 5. You are given the number that have MORE than 15 years service, but the complement of that set is the number that have LESS than or EQUAL to 15 years service. So to answer number 5 you must find the number of single males with less than or equal to 15 years service and subtract the number of single males with EXACTLY 15 years service. You cannot determine the cardinality of that last set from the data given.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I > Ø \n" ); document.write( " |