document.write( "Question 1167840: A square and an equilateral triangle have the same perimeter. The area of the square is 13 more than the length of a side of the triangle. What is the length of a side in the triangle (in inches)? What is the area of the square (in square inches)? \n" ); document.write( "
Algebra.Com's Answer #792442 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! side of triangle is s \n" ); document.write( "perimeter is 3s\r \n" ); document.write( "\n" ); document.write( "so side of square is 0.75 s for perimeter of 3s\r \n" ); document.write( "\n" ); document.write( "The square's area is 0.5625 s^2 and that is 13 more than area of triangle. \n" ); document.write( "the area of an equilateral triangle is (1/2)(s)*(s/2)(sqrt(3)=(1/4)s^2(sqrt(3)\r \n" ); document.write( "\n" ); document.write( "therefore (9/16)s^2-13=sqrt(3)/4 s^2, converting to fractional form \n" ); document.write( "or (9/16)s^2-13=4 sqrt(3)s^2/16 \n" ); document.write( "and 9s^2-208=4 sqrt(3)s^2 \n" ); document.write( "[9-4 sqrt(3)]s^2=208 \n" ); document.write( "2.072 s^2=208 \n" ); document.write( "s^2=208/(9-4 sqrt(3)) \n" ); document.write( "s=10.02 inches, side of the triangle; side of square is 7.51 inches\r \n" ); document.write( "\n" ); document.write( "Check this. \n" ); document.write( "A square is 56.47 in^2 (I didn't round until the last step)\r \n" ); document.write( "\n" ); document.write( "side of triangle is 10.02 in. \n" ); document.write( "altitude is 5.01*sqrt(3) in=8.68 inches \n" ); document.write( "Area of triangle is 43.47 in^2,\r \n" ); document.write( "\n" ); document.write( "The answer is 10.02 inches for the triangle and 56.47 in^2 for the square\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |