document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1167841>Question 1167841</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist wants to make 42 ml of a 16% acid solution by mixing an 11% acid solution and an 18% acid solution. How many milliliters of each solution should the chemist use? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #792438 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=792438\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x ml of 11%<BR>\n" );
document.write( "42-x ml of 18%<BR>\n" );
document.write( ".11x+.18(42-x)=42*0.16=6.72 ml pure acid<BR>\n" );
document.write( ".11x+7.56-.18x=6.72<BR>\n" );
document.write( "-0.07x=-0.84<BR>\n" );
document.write( "x=12 ml of 11%<BR>\n" );
document.write( "42-x=30 ml of 18%\r<BR>\n" );
document.write( "\n" );
document.write( "Also,<BR>\n" );
document.write( "16% is 5/7 of the way from 11 to 18%<BR>\n" );
document.write( "want 5/7 of the higher percent and 2/7 of the lower<BR>\n" );
document.write( "with 42 ml, that is 30 ml of 18% and 12 ml of 12%. </SPAN>\n" );
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