document.write( "Question 1167810: A conference spent $108 on 154 servings of cantaloupe and honeydew. If a cantaloupe melon costs $3 and serves four while a honeydew melon costs $4 and serves six, how many honeydew melons did the organizers buy? \n" ); document.write( "
Algebra.Com's Answer #792408 by ikleyn(52781)\"\" \"About 
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\n" ); document.write( "A conference spent $108 on 154 servings of cantaloupe and honeydew. If a cantaloupe melon costs $3 and serves four
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document.write( "Let x = the number of honeydew servings.\r\n" );
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document.write( "Then the number of the cantaloupe servings is (154-x).\r\n" );
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document.write( "Each single honeydew   serving costs \"4%2F6\" = \"2%2F3\"  dollars;\r\n" );
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document.write( "Each single cantaloupe serving costs \"3%2F4\"  dollars.\r\n" );
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document.write( "Write the money equation\r\n" );
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document.write( "    \"%282%2F3%29x+%2B+%283%2F4%29%2A%28154-x%29\" = 108  dollars.\r\n" );
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document.write( "Multiply both sides by 12\r\n" );
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document.write( "    8x + 9*(154-x) = 12*108.\r\n" );
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document.write( "From the equation\r\n" );
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document.write( "    x = \"%2812%2A108-9%2A154%29%2F%288-9%29\" = 90.\r\n" );
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document.write( "90 honeydew servings means  \"90%2F6\" = 15  honeydew mellons.\r\n" );
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document.write( "ANSWER.  15  honeydew mellons.\r\n" );
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