document.write( "Question 108670This question is from textbook
\n" ); document.write( ": One positive number is three more than twice another. If the product is 27, find the numbers.\r
\n" ); document.write( "\n" ); document.write( "?? So stumped...please help~
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Algebra.Com's Answer #79240 by wgunther(43)\"\" \"About 
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Let a be the first integer, and let b be the second.\r
\n" ); document.write( "\n" ); document.write( "We know the following facts.\r
\n" ); document.write( "\n" ); document.write( "\"%0D%0Aa=2b%2B3%0D%0A\"
\n" ); document.write( "\"%0D%0Aab=27\"\r
\n" ); document.write( "\n" ); document.write( "we can solve by substitution. Since a is 2b+3 we can subsitute that into the second equation.\r
\n" ); document.write( "\n" ); document.write( "\"%0D%0Ab%282b%2B3%29=27%0D%0A\"
\n" ); document.write( "\"2b%5E2%2B3b-27=0\"
\n" ); document.write( "\"%282b%2B9%29%28b-3%29=0\"\r
\n" ); document.write( "\n" ); document.write( "So, be is 2/9 or 3. But, 2/9 is not an integer, so b=3. a=2b+3 which is 9.
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