document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=108655>Question 108655</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A coffee merchant has coffee beans that sell for $9 per<BR>\n" );
document.write( "pound and $12 per pound. The two types are to be mixed to create 100 lb of a mixture<BR>\n" );
document.write( "that will sell for $11.25 per pound. How much of each type of bean should be<BR>\n" );
document.write( "used in the mixture? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #79239 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=79239\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let n=# of lbs of $9/lb; t=# of lbs of $12/lb<BR>\n" );
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document.write( "A) n+t=100<BR>\n" );
document.write( "B) 9n+12t=1125<BR>\n" );
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document.write( "A) n=100-t<BR>\n" );
document.write( "B) 9(100-t)+12t=1125<BR>\n" );
document.write( "900-9t+12t=1125<BR>\n" );
document.write( "3t+900=1125<BR>\n" );
document.write( "3t+900-900=1125-900<BR>\n" );
document.write( "3t=225<BR>\n" );
document.write( "t=75 lbs<BR>\n" );
document.write( "n=25 lbs<BR>\n" );
document.write( "Always check:<BR>\n" );
document.write( "9*25+12*75=1125 true<BR>\n" );
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document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );