document.write( "Question 1167776: julia is 4 years older than jane. Maria is three times as old as Jane. The sum of their age is 54. find the age of each \r
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document.write( "Donna is 4 years younger than Bob. Jake is four times as old as Bob. The sum of their age is 110. find the age of each\r
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document.write( "the larger of two numbers is 12 less than three times the smaller. If their sum is 28, find the numbers\r
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document.write( "Charles is 4 years older than his wife Diana. The sum of their age is 52. What are their present age \n" );
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Algebra.Com's Answer #792378 by josgarithmetic(39630) ![]() You can put this solution on YOUR website! (1) Too many separate questions in one posting\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(2) The other one recently answered should be enough help already for these types of exercises. \n" ); document.write( " |