document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1167758>Question 1167758</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A random sample of 20 acres gave a mean yield of sugarcane equal to 41.2 tons per acre with a<BR>\n" );
document.write( "standard deviation of 3 tons. Assuming that the yield of sugarcane per acre is normally<BR>\n" );
document.write( "distributed,<BR>\n" );
document.write( "a. Construct a 90% confidence interval for the population mean.<BR>\n" );
document.write( "b. What is the margin of error for this estimate in part a?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #792365 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=792365\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 90% CI half-interval for a sample of 20 is t(0.95, df=19)* s/sqrt(n)<BR>\n" );
document.write( "=1.729*3/sqrt(20)=1.16 tons/acre. This is the margin of error.<BR>\n" );
document.write( "the 90% CI is (40.04, 42.36) units tons/acre </SPAN>\n" );
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