document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1167535>Question 1167535</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The distribution of scores on a standardized test is approximately Normal with standard deviation of σ = 17. If a sample of 135 students had a mean score of x¯ = 75.2, use this to find a 99% confidence interval for the mean score of all students on this test.\r<BR>\n" );
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document.write( "We are 99% confident that the the mean score of students on this test was in the interval </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #792349 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=792349\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 99%CI is mean +/-z(0.995)*sigma/sqrt(n)<BR>\n" );
document.write( "this is mean +/-2.576*17/sqrt(135)<BR>\n" );
document.write( "=mean +/-3.769<BR>\n" );
document.write( "the interval is (71.431, 78.769) </SPAN>\n" );
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