document.write( "Question 1167746: At noon Shawna left her home headed to Rochester, traveling at an average rate of 38 mi/hr. Her brother Terrance left 2 hr later, traveling at an average rate of 43 mi/hr, and was 56 mi behind Shawna when she arrived in Rochester. How far is it from their home to Rochester, and how long did it take for Shawna to make the drive? 228 m \n" ); document.write( "
| Algebra.Com's Answer #792347 by Boreal(15235)     You can put this solution on YOUR website! Her brother left 2 hours later and was 76 miles behind. He was driving 5 mph faster than she was, so he gained 5 miles every hour and it took 4 hours for him to be 56 miles behind her. \n" ); document.write( "43*4=172 miles \n" ); document.write( "she was 56 miles ahead when she arrived, so the total distance was 228 miles \n" ); document.write( "At 38 mph, it took her 6 hours.\r \n" ); document.write( "\n" ); document.write( "also \n" ); document.write( "Shawna drove x hours and made 38x miles \n" ); document.write( "Terrance drove x-2 hours and made 43(x-2) or 43x-86 miles \n" ); document.write( "43x-86=38x-56 when she arrived in Rochester. \n" ); document.write( "5x=30 or \n" ); document.write( "x=6 hours \n" ); document.write( "distance total is 228 miles. \n" ); document.write( " \n" ); document.write( " |