document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1167722>Question 1167722</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two cyclists start from the same point and ride in opposite directions. One cyclist. One cyclist rides twice as fast as the other. In 3 h, they are 90 mi apart. Find the rate of each cyclist. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #792318 by </B><A HREF=/tutors/aboutme.mpl?userid=dkppathak><B>dkppathak(439)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dkppathak><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=dkppathak><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=792318\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two cyclists start from the same point and ride in opposite directions. One cyclist. One cyclist rides twice as fast as the other. In 3 h, they are 90 mi apart. Find the rate of each cyclist.<BR>\n" );
document.write( "let speed of first cyclist is x mile /hours and other is twice means 2x mile/hours <BR>\n" );
document.write( "distance traveled  by both in  3 hrs will be 3x and 6x miles  <BR>\n" );
document.write( "both are in opposite direction <BR>\n" );
document.write( "total distance will be 3x+6x=90 <BR>\n" );
document.write( "9x=90<BR>\n" );
document.write( "x=90/9=10 miles /hours <BR>\n" );
document.write( "Answer <BR>\n" );
document.write( "10 miles/hours and 20 miles /hours  </SPAN>\n" );
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