document.write( "Question 1167702: A car and a bus set out at 6 P.M. from the same point headed in the same direction. The average speed of the car is twice the average speed of the bus. In 2 h, the car is 68 mi ahead of the bus. Find the rate of the car. \n" ); document.write( "
Algebra.Com's Answer #792301 by Theo(13342)\"\" \"About 
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r * t = d
\n" ); document.write( "r = rate
\n" ); document.write( "t = time
\n" ); document.write( "d = distance.\r
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\n" ); document.write( "\n" ); document.write( "if r = rate of the bus, then 2r = rate of the car.
\n" ); document.write( "if x is the distance that the bus travels, then x + 68 is the distance the car traveled.\r
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\n" ); document.write( "\n" ); document.write( "when time = 2, you get:\r
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\n" ); document.write( "\n" ); document.write( "2r * 2 = x + 68 for the car.
\n" ); document.write( "r * 2 = x for the bus.\r
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\n" ); document.write( "\n" ); document.write( "simplify to get:\r
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\n" ); document.write( "\n" ); document.write( "4r = x + 68 for the car.
\n" ); document.write( "2r = x for the bus.\r
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\n" ); document.write( "\n" ); document.write( "subtract the second equation from the first to get:\r
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\n" ); document.write( "\n" ); document.write( "2r = 68\r
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\n" ); document.write( "\n" ); document.write( "solve for r to get:\r
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\n" ); document.write( "\n" ); document.write( "r = 35\r
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\n" ); document.write( "\n" ); document.write( "the rate of the bus = 34 miles per hour.
\n" ); document.write( "the rate of the car = 68 miles per hour.\r
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\n" ); document.write( "\n" ); document.write( "in 2 hours, the car travels 68 * 2 = 136 miles.
\n" ); document.write( "in 2 hours, the bus travels 34 * 2 = 68 miles.\r
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\n" ); document.write( "\n" ); document.write( "the car travels 68 miles more than the bus in the same time.\r
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\n" ); document.write( "\n" ); document.write( "your solution is the rate of the car = 68 miles per hour.\r
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