document.write( "Question 1167707: A baseball diamond is shown. The four corners of the diamond are \"Home plate,\" \"1st base,\" \"2nd base,\" and \"3rd base.\" There is a mound near the center of the diamond. The following measurements are given.
\n" ); document.write( "Each side of the diamond is labeled 90 ft.
\n" ); document.write( "The distance between \"Home plate\" and the mound near the center of the diamond is labeled 60 ft, 6 inches.
\n" ); document.write( "In baseball, the pitcher's mound is 60 feet, 6 inches from home plate. How far (in ft) from the mound is second base? \r
\n" ); document.write( "\n" ); document.write( "The answer is not 127ft \n" ); document.write( "

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Of course it is not 127ft, that is the distance from home plate to 2nd base
\n" ); document.write( "( $\"sqrt%2890%5E2+%2B+90%5E2%29+=+90%2Asqrt%282%29+=+127.28ft+\"$ )
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\n" ); document.write( "Subtract 60ft 6in (60.5ft) from 127.28ft to get the mound-to-2nd base distance:
\n" ); document.write( "66.78ft or approx. 66ft 9in.\r
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