document.write( "Question 1167690: Ryan is 44 years younger than Katie. 6 years ago, Katie's age was 3 times Ryan's age. How old is Ryan now?\r
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Algebra.Com's Answer #792281 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Algebraically....

\n" ); document.write( "x = Ryan's age
\n" ); document.write( "x+44 = Katie's age
\n" ); document.write( "x-6 = Ryan's age 6 years ago
\n" ); document.write( "x+44-6 = x+38 = Katie's age 6 years ago

\n" ); document.write( "Katie's age 6 years ago was 3 times Ryan's age then:

\n" ); document.write( "\"x%2B38+=+3%28x-6%29\"

\n" ); document.write( "Solve using basic algebra; I leave that to you.

\n" ); document.write( "Using logical reasoning and some easy mental arithmetic....

\n" ); document.write( "6 years ago, Katie's age was 3 times Ryan's age. Let their ages then be 3x and x; the difference in their ages is 2x.

\n" ); document.write( "The difference in their ages is 44 years. So 6 years ago

\n" ); document.write( "\"2x+=+44\"
\n" ); document.write( "\"x+=+22\"

\n" ); document.write( "So their ages 6 years ago were x=22 and 3x=66.

\n" ); document.write( "So their ages now are 22+6=28 and 66+6=72.

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