document.write( "Question 1167603: It is reported that 77% of workers aged 16 and over drive to work alone. Choose 8 workers at random. Find the probability that\r
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document.write( "a. All drive to work alone\r
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document.write( "b. More than one half drive to work alone\r
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document.write( "c. Exactly 3 drive to work alone \n" );
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Algebra.Com's Answer #792229 by Boreal(15235) You can put this solution on YOUR website! a. This is .77^8=0.1236 \n" ); document.write( "c. exactly 3 is 8C3*.77^3*.23^5=0.0165 \n" ); document.write( "b. look at 0,1,2, and 3 and subtract that sum from 1. \n" ); document.write( "have 3 \n" ); document.write( "for 1 it is 8*0.77*0.23^7=0.0002 \n" ); document.write( "for 0 it is <0.0001 (.23^8) \n" ); document.write( "for 2 it is 28*0.77^2*0.23^6=0.0024 \n" ); document.write( "for 4 it is 70*0.77^4*0.23^4=0.0689\r \n" ); document.write( "\n" ); document.write( "for <=4 it is probability 0.0880, so the answer is the complement or 0.9120 \n" ); document.write( " \n" ); document.write( " |