document.write( "Question 1167551: A circle is inscribed inside an equilateral triangle. If the circumference of the circle is 6 cm, then the area of the triangle, in cm^2 is:\r
\n" ); document.write( "\n" ); document.write( "A) 27 √3 π
\n" ); document.write( "B) 27 √3/π
\n" ); document.write( "C) 27 √3/π^2
\n" ); document.write( "D) 9 √3/π^2
\n" ); document.write( "E) 9 √3 π
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Algebra.Com's Answer #792187 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Draw the figure.

\n" ); document.write( "Draw the three altitudes of the equilateral triangle, intersecting at the center of the circle. Those altitudes divide the equilateral triangle into six congruent 30-60-90 right triangles, in which the ratio of the side lengths is 1:sqrt(3):2.

\n" ); document.write( "(1) The circumference of the circle is 6; find the radius using \"c+=+2%28pi%29r\".

\n" ); document.write( "(2) The radius of the circle is the short leg of one of the 30-60-90 right triangles. Use the radius from (1) and the ratio 1:sqrt(3):2 to find the long leg of each of the 30-60-90 triangles.

\n" ); document.write( "(3) The side length of the triangle is twice the length found in (2).

\n" ); document.write( "(4) The area of an equilateral triangle with side length s is \"s%5E2%2Asqrt%283%29%2F4\".

\n" ); document.write( "If you do all those calculations correctly, you should finish with answer choice C.

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