document.write( "Question 1167553: Beginning at the origin, a spiral is constructed from 3 semi circles with centres at (1,0),(0,0),(2,0). The area of the shaded region, in u^2 is:\r
\n" ); document.write( "\n" ); document.write( "A) 7 π-2 √3/6
\n" ); document.write( "B) 8 π-√3/3
\n" ); document.write( "C)8 π-6 √3/3
\n" ); document.write( "D) 3 π -2 √3
\n" ); document.write( "E) 11 π -6√3/3\r
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\n" ); document.write( "\n" ); document.write( "https://imageshack.com/i/pmBbsOMDj
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Algebra.Com's Answer #792184 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "Call the origin O. Let A(2,0) be the center of the third semicircle, and let B(0,b) be the y-intercept of that third semicircle.

\n" ); document.write( "Triangle AOB is a 30-60-90 right triangle, because OA=2 and AB=4. That makes OB \"2%2Asqrt%283%29\".

\n" ); document.write( "The shaded region is (a) one-half the area of the second semicircle with radius 2, plus (b) one-third the area of the third semicircle (because angle BAO is 60 degrees), minus (c) the area of triangle AOB.

\n" ); document.write( "(a) \"%281%2F2%29%28pi%282%5E2%29%2F2%29+=+pi\"
\n" ); document.write( "(b) \"%281%2F3%29%28pi%284%5E2%29%2F2%29+=+%288%2F3%29pi\"
\n" ); document.write( "(c) \"%281%2F2%29%282sqrt%283%29%29%282%29+=+2sqrt%283%29\"

\n" ); document.write( "ANSWER: \"pi%2B%288%2F3%29pi-2sqrt%283%29+=+%2811%2F3%29pi-2sqrt%283%29\"

\n" ); document.write( "Note answer choices A, B, C, and E are all shown incorrectly, because required parentheses are missing.

\n" ); document.write( "Answer choice E is supposed to be the right answer: \"%2811pi-6sqrt%283%29%29%2F3\"

\n" ); document.write( "But answer choice E as shown, \"11pi-6sqrt%283%29%2F3\", is incorrect.

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