document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1167531>Question 1167531</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a wall is 12m more than it's width. If the area of the wall is 50m² what could be it's length? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #792119 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=792119\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> w(w+12)=50<BR>\n" );
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document.write( "L(L-12)=50 for length multiplied by width\r<BR>\n" );
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document.write( "L^2-12L-50=0\r<BR>\n" );
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document.write( "L=(12+- sqrt(144+4*50))/2\r<BR>\n" );
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document.write( "L=(12+- sqrt(344))/2\r<BR>\n" );
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document.write( "L=(12+- 2sqrt(86))/2\r<BR>\n" );
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document.write( "L=6+- sqrt(86)\r<BR>\n" );
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document.write( "L=6+9.27\r<BR>\n" );
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