document.write( "Question 1167462: Can the below be factored since it does not have all like characters?\r
\n" ); document.write( "\n" ); document.write( "4a^2 + 16ab + 16b^2 =\r
\n" ); document.write( "\n" ); document.write( "Also, have I correctly factored ax^2 -a = To be a(a+1)(a-1)\r
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Algebra.Com's Answer #792036 by ikleyn(53938)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "1)   Can the below be factored since it does not have all like characters?     4a^2 + 16ab + 16b^2\r
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document.write( "    Yes it can be factored.\r\n" );
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document.write( "        4a^2 + 16ab + 16b^2  =  (2a + 4b)^2.\r\n" );
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\n" ); document.write( "\n" ); document.write( "2)   Also, have I correctly factored ax^2 -a = To be a(a+1)(a-1)\r
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document.write( "    Your \"factoring\" is WRONG.\r\n" );
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document.write( "    The correct factoring is  ax^2 -a = a*(x+1)*(x-1).\r\n" );
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\n" ); document.write( "\n" ); document.write( "By the way,  when you pose your question this way\r
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document.write( "    Can the below be factored since it does not have all like characters?\r\n" );
document.write( "    4a^2 + 16ab + 16b^2\r\n" );
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\n" ); document.write( "\n" ); document.write( "you make several logical/mathematical errors simultaneously.\r
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\n" ); document.write( "\n" ); document.write( "First is that  \" it does not have all like characters \".\r
\n" ); document.write( "\n" ); document.write( "             In contrary,  it has the common factor 4.\r
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\n" ); document.write( "\n" ); document.write( "Second,  in order for an expression could be factored,  it is  NOT  NECESSARY  to have all like characters:\r
\n" ); document.write( "\n" ); document.write( "             a^2 - b^2 = (a+b)*(a-b).\r
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