document.write( "Question 1167413: Hi
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document.write( "Alan and Joe had the same amount of money. Alan spent 0.7 of his money while joe spent 0.2 . Joe bought 4 pens for $36 and found that he had twice as much money as Alan had left . How much money did they have altogether. \r
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Algebra.Com's Answer #792004 by Theo(13342)![]() ![]() You can put this solution on YOUR website! i believe the problem statement should have been as follows:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Alan and Joe had the same amount of money. \n" ); document.write( "Alan spent 0.7 of his money while joe spent 0.2 of his money. \n" ); document.write( "Joe THEN bought 4 pens for $36 and found that he had twice as much money as Alan had left. \n" ); document.write( "How much money did they have altogether?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when stated like this, you get the following.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Alan spent .7 * x, so he had .3 * x left.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Joe spent .2 * x, so he had .8 * x left.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "joe then spent an additional 36 dollars.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this means he had .8 * x - 36 dollars left.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "he then found that he had twice as much money left as Alan had.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this means that:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".8 * x - 36 = 2 * .3 * x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "simplify to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".8 * x - 36 = .6 * x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "subtract .6 * x from both sides of this equation and add 36 to both sides of this equation to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".2 * x = 36\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for x to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 36 / .2 = 180.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this says they each had 180 dollars to start with.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "alan spent 70% and so he had 30% left = .3 * 180 = 54 left.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "joe spent 20% and so he had 80% left = .8 * 180 = 144 left.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "joe then spent an additional 36 dollars and so he had 144 - 36 = 108 left.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "he found that he had twice as money left as alan had left.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "108 / 54 = 2, confirming what he found was correct.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since they each had 180 dollars to start with, then they both had 2 * 180 = 360 dollars to start with.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your solution is that the money that they had all together was 360 dollars before they had spent any money.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the original problem statement was confusing.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "it was not clear that the 36 dollars that was spent was after .2 * x was spent.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i originally thought that the 36 dollars represented the .2 * x that was spent.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "it turned out that, assuming that .2 * x = 36 provided me with logical inconsistencies that couldn't be resolved.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "assuming the 36 was spent in addition to the .2 * x that was already spent removed the logical inconsistencies and so i went with that.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |