document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1167320>Question 1167320</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a geometric sequence whose first three terms are 9, -6, 4, ..., which term is 1024/6561? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #791941 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=791941\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Consecutive terms have a ratio of -2/3, and the number of terms has to be even, because it is positive.<BR>\n" );
document.write( "9(-2/3)^x=1024/6561=2^10/3^8. But we started with 9, or 3^2, so this is 10 terms<BR>\n" );
document.write( "9*(-2/3)^10=1024/6561\r<BR>\n" );
document.write( "\n" );
document.write( "10th term.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );