document.write( "Question 1167241: Jaydens brother is 7 years older than jayden. His mother is 4 less than 3 times jaydens age. Their combined age is 103.How old is jayden his brother and his mother \n" ); document.write( "
Algebra.Com's Answer #791845 by VFBundy(438)\"\" \"About 
You can put this solution on YOUR website!
Jayden's age = j
\n" ); document.write( "Jayden's brother's age = j + 7
\n" ); document.write( "Jayden's mother's age = 3j - 4
\n" ); document.write( "
\n" ); document.write( "j + (j + 7) + (3j - 4) = 103
\n" ); document.write( "
\n" ); document.write( "j + j + 7 + 3j - 4 = 103
\n" ); document.write( "
\n" ); document.write( "5j + 3 = 103
\n" ); document.write( "
\n" ); document.write( "5j = 100
\n" ); document.write( "
\n" ); document.write( "j = 20
\n" ); document.write( "
\n" ); document.write( "Jayden's age = j = 20
\n" ); document.write( "Jayden's brother's age = j + 7 = 20 + 7 = 27
\n" ); document.write( "Jayden's mother's age = 3j - 4 = 3(20) - 4 = 60 - 4 = 56
\n" ); document.write( "
\n" );