document.write( "Question 108584: Suppose that the function P=13+45x represents the percentage of inbound e-mail in the U.S. that is considered spam, where x is the number of years after 2000.\r
\n" ); document.write( "\n" ); document.write( "Use this model to approximate the year that the percent of spam will reach 95% provided that law enforcement regarding spammers does not change. \r
\n" ); document.write( "\n" ); document.write( "I have tried this 2000(.95)=13+45ln(2000) This did not work out
\n" ); document.write( "Then I tried 2000(.95)=1345ln(2000)(.95)This did not work either.\r
\n" ); document.write( "\n" ); document.write( "Thank you
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Algebra.Com's Answer #79182 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
The function P=13+45x represents the percentage of inbound e-mail in the U.S. that is considered spam, where x is the number of years after 2000.
\n" ); document.write( "Use this model to approximate the year that the percent of spam will reach 95% provided that law enforcement regarding spammers does not change.
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\n" ); document.write( "Read it again closely; it says x = \"number of year after 2000\"
\n" ); document.write( "Another words in 2000, x = 0; 2001, x = 1; 2002, x = 2 etc
\n" ); document.write( "The number 2000 does not enter into the calculation
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\n" ); document.write( "It's not near that complicated
\n" ); document.write( "I don't think they want you to convert % to a decimal
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\n" ); document.write( "13 + 45x = 95
\n" ); document.write( "45x = 95-13
\n" ); document.write( "45x = 82
\n" ); document.write( "x = 82/45
\n" ); document.write( "x = 1.8 years which is close to 2002
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\n" ); document.write( "We can say in the year 2000 (x=0) the spam amt was 13%
\n" ); document.write( "and in the year 2001 (x=1) the spam amt jumps to 13 + 45 = 58%
\n" ); document.write( "and in the year 2002 (x=2) the spam amt jumps to 13 + 90 = 100% is the max
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\n" ); document.write( "Did this help?\r
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