document.write( "Question 1167077: A bag initially had blue, red, and purple gumballs in the ration 2 : 3 : 5. Let N be the
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document.write( "number of red gumballs added to the bag, and 2N be the number of purple gumballs
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document.write( "added to the bag. How many blue gumballs we need to add , in the bag so that the
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document.write( "probability of drawing a blue gumball, a red gumball and a purple gumball is now 1/6,
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document.write( "2/6, and 3/6, respectively?
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document.write( "A) is equal to N
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document.write( "B) is equal to 2N
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document.write( "C) is less than N
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document.write( "D) is greater than N but less than 2N
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document.write( "E) cannot be determined
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Algebra.Com's Answer #791727 by greenestamps(13203) You can put this solution on YOUR website! \n" ); document.write( "A curious problem -- I have to wonder if the information given is not correct. \n" ); document.write( "Defining N as the number of red gumballs added to the bag suggests that N should be a positive integer; but it turns out to be negative.... \n" ); document.write( "Given the original ratio 2:3:5... \n" ); document.write( "let 2x = number of blue originally \n" ); document.write( "let 3x = number of red originally \n" ); document.write( "let 5x = number of purple originally \n" ); document.write( "let A be the number of blue to be added. Then after adding more gumballs, \n" ); document.write( "2x+A = number of blue \n" ); document.write( "3x+N = number of red \n" ); document.write( "5x+2N = number of purple \n" ); document.write( "After more gumballs are added, the probability of drawing a blue is 1/6, the probability of drawing a red is 2/6, and the probability of drawing a purple is 3/6. That means the number of red is 2 times the number of blue, and the number of purple is 3 times the number of blue. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So now \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So the answer to the problem as stated is answer A: the number of blue gumballs to be added is equal to N. \n" ); document.write( "But now let's put some actual numbers in the problem. \n" ); document.write( "The number of blue gumballs is now 2x+N, and the number of red gumballs is 3x+N. \n" ); document.write( "And since the probability of drawing a red is 2/6 while the probability of drawing a blue is 1/6, the number of red gumballs is twice the number of blue gumballs: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Now what we have is this: \n" ); document.write( "original number of blue gumballs: 2x \n" ); document.write( "original number of red gumballs: 3x \n" ); document.write( "original number of purple gumballs: 5x \n" ); document.write( "number of blue gumballs \"added\": -x \n" ); document.write( "number of red gumballs \"added\": -x \n" ); document.write( "number of purple gumballs \"added\": -2x \n" ); document.write( "ending number of blue gumballs: 2x-x = x \n" ); document.write( "ending number of red gumballs: 3x-x = 2x \n" ); document.write( "ending number of purple gumballs: 5x-2x = 3x \n" ); document.write( "And we see from this that the final condition of the problem is satisfied: \n" ); document.write( "P(blue) = x/6x = 1/6 \n" ); document.write( "P(red) = 2x/6x = 2/6 \n" ); document.write( "P(purple) = 3x/6x = 3/6 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |