document.write( "Question 1167124:  The following data are the distances between a sample of 20 retail stores and a large distribution center. The distances are in miles.\r
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document.write( "29; 30; 37; 40; 58; 67; 68; 69; 76; 81; 84; 95; 96; 96; 99; 106; 112; 127; 145; 150\r
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document.write( "How do I find the value that is one standard deviation below the mean. (I have to round the answer to one decimal place.)\r
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document.write( "Thanks to anyone who can help explain this to me. I appreciate you all for taking the time out of your day to help students like me understand math problems. \n" );
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| Algebra.Com's Answer #791709 by ikleyn(52879)     You can put this solution on YOUR website! .\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "As I understand the problem, you should find the mean and the standard deviation, and then subtract one standard deviation from the mean.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "How to find a mean and how to find a standard deviation is written in any of numerous textbooks in statistics.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You also can find tens sites in the Internet with free of charge online solvers,\r \n" ); document.write( "\n" ); document.write( "that will make all this routine job for you, as soon as you input your data.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In parallel, these sites will teach you everything that you need to know about the subject.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Key words: mean, standard deviation, online calculator.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |