document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1166991>Question 1166991</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi, if you can help me with this problem, it would be greatly appreciated! Thank you in advance!\r<BR>\n" );
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document.write( "A sample of 100 clients of an exercise facility was selected. Let X = the number of days per week that a randomly selected client uses the exercise facility.\r<BR>\n" );
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document.write( "X	 Frequency<BR>\n" );
document.write( "0	  2<BR>\n" );
document.write( "1	 13<BR>\n" );
document.write( "2	 31<BR>\n" );
document.write( "3	 29<BR>\n" );
document.write( "4	 11<BR>\n" );
document.write( "5	 7<BR>\n" );
document.write( "6	 7\r<BR>\n" );
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document.write( "Find the number that is 1.5 standard deviations BELOW the mean. (I also have to round the answer to three decimal places.) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #791672 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=791672\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> i get:<BR>\n" );
document.write( "mean = 2.848485 rounded to 6 decimal places.<BR>\n" );
document.write( "standard deviation = 1.416835 rounded to 6 decimal places.\r<BR>\n" );
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document.write( "1.5 standard deviations below the mean would be equal to:\r<BR>\n" );
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document.write( "2.848485 - 1.5 * 1.416835 = .7232325\r<BR>\n" );
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document.write( "round that to 3 decimal places to get .723.\r<BR>\n" );
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document.write( "the derivation of the mean and the standard deviation is shown below:\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );