document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1167095>Question 1167095</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Maggie, Amy, and Karen are relatives. They have lived a total of 105 years combined. Maggie's age is 25 years than three times Karen's age. Amy's age is twice the sum of Maggie and Karen's ages. Find the age of each woman </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #791666 by </B><A HREF=/tutors/aboutme.mpl?userid=dkppathak><B>dkppathak(439)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dkppathak><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=dkppathak><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=791666\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Maggie, Amy, and Karen are relatives. They have lived a total of 105 years combined. Maggie's age is 25 years than three times Karen's age. Amy's age is twice the sum of Maggie and Karen's ages. Find the age of each woman<BR>\n" );
document.write( "solutions<BR>\n" );
document.write( "Maggie+Amy+Karen=105 Given 1<BR>\n" );
document.write( "Maggie=25+3Karen<BR>\n" );
document.write( "Ammy=2(Maggies+Karen)<BR>\n" );
document.write( "Ammy=2(25+3karen+Karen )=50+8 Karen  putting value in 1 conditions <BR>\n" );
document.write( "25+3Karen+50+8Karen+Karen=105<BR>\n" );
document.write( "75+12Karen=105<BR>\n" );
document.write( "12Karen=105-75=30<BR>\n" );
document.write( "Karen=30/12=2.5 yrs <BR>\n" );
document.write( "Maggie=25+3x2.5=25+7.5=32.5 yrs<BR>\n" );
document.write( "Amy=50+8 Karen=50+8x2.5=70 yrs <BR>\n" );
document.write( "Verification <BR>\n" );
document.write( "Maggie+Amy+karen=32.5+70+2.5=105<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );