document.write( "Question 1166483: A set of exam scores is normally distributed with a mean = 76 and standard deviation = 7.
\n" ); document.write( "Use the Empirical Rule to complete the statements below.\r
\n" ); document.write( "\n" ); document.write( "95% of the data values lie between 62 and 90\r
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\n" ); document.write( "\n" ); document.write( "% of the exam scores are less than or equal to 76.\r
\n" ); document.write( "\n" ); document.write( "% of the exam scores are less than or equal to 69.\r
\n" ); document.write( "\n" ); document.write( "% of the exam scores are less than or equal to 90.\r
\n" ); document.write( "\n" ); document.write( "% of the exam scores are less than or equal to 83.
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Algebra.Com's Answer #791627 by Boreal(15235)\"\" \"About 
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half the scores are les than the mean,'
\n" ); document.write( "68% of the scores are between -1 and +1 sd, so 16% on each side are outside that value. It would be 16% score fewer than a 69.
\n" ); document.write( "0.025 score greater than or equal to 90 so 0.975 or 97.5%score less than 90.
\n" ); document.write( "and 0.84 or 84% score less than 83.
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