document.write( "Question 1167042: a rectangle is drawn so the width is 9 inches longer than the height. If the rectangle's diagonal measurement is 45 inches, find the height \n" ); document.write( "
Algebra.Com's Answer #791613 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "The side lengths are x and x+9.

\n" ); document.write( "Two sides and the diagonal form a right triangle. Solve using the Pythagorean Theorem.

\n" ); document.write( "\"x%5E2%2B%28x%2B9%29%5E2+=+45%5E2\"
\n" ); document.write( "\"x%5E2%2Bx%5E2%2B18x%2B81+=+2025\"
\n" ); document.write( "\"2x%5E2%2B18x-1944+=+0\"
\n" ); document.write( "\"x%5E2%2B9x-972+=+0\"

\n" ); document.write( "Solve by factoring, or using the quadratic formula, or with a graphing calculator....

\n" ); document.write( "If a formal algebraic solution is not required, the solution can be found quickly knowing that the side lengths are integers -- so the three side lengths are a Pythaogrean Triple.

\n" ); document.write( "The smallest Pythagorean Triple is 3-4-5. Since the diagonal of the rectangle (hypotenuse of the right triangle) is 45, try 27-36-45 for the side lengths of the triangle.

\n" ); document.write( "Those side lengths satisfy the conditions of the problem....

\n" ); document.write( "ANSWER: The height is 27; the width is 36.

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